I can't do this...?

Consider the following frequency distribution that shows the distribution of shoe sizes in a women’s clothing store:


Shoe Size Pairs in stock


5 15


6 25


7 40


8 30


9 20


The department manager makes a random selection of a pair of shoes to show a customer.











6. The probability that the selected shoe is a size 7 or larger is (1 point)


a. 0.38 b. 0.40


c. 0.69 d. 1.0





7. The probability that the selected shoe is size 6 or less is (1 point)


a. 0.12 b. 0.19


c. 0.31 d. 1.0

I can%26#039;t do this...?
its a fraction, all you have to do is add all of the times the shoes sizes have been picked which would be


15 + 25 + 40 + 30 + 20= 130


this would be the denominator of the fraction( which is the bottom part)


then for the numerator ( the top part of the fraction) you add all of the times the shoes sizes have been picked, but only the ones of the sizes 7 8 and 9 9cause thats what the question is asking, which would be:


(40 + 30 + 20) = 90


so the fraction would be 90/130


then you divide that in teh calculator (90 divided by 130) which is:


90 / 130 = 0.69 ( thats C)


and then you do the same with number 7, but with teh shoes sizes 6 and 5, so it would be:


7. (15 + 25) / (15 + 25 + 40 + 30 + 20) = 40 / 130 = 0.31


hope i helped :)
Reply:WEIRD!





they are trick questions!!!!


there is no answer!
Reply:huh?
Reply:6. (40 + 30 + 20) / (15 + 25 + 40 + 30 + 20) = 90 / 130 = 0.69 so (C)





7. (15 + 25) / (15 + 25 + 40 + 30 + 20) = 40 / 130 = 0.31 so (C)
Reply:cheatingg



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