Some Counting Principal Questions! Help!!!?

Can you tell me if I am correct on these??? Thanks.


a. A sporting goods store stocks 10 styles of shoes. Each style comes in 8 sizes and 5 colors. How many shoes must the store stock in order tohave one pair of each size?


(10)8(5) = 400???


b. A business women has 8 skirts and 4 sweaters. How many different outfits can she make? 4*8 = 32?


c. A menu contains 5 main dishes, 3 side dishes, 2 salads, and 4 desserts. How many different meals can be made with the section? 5x3x2x4?? 240???


d. How many ways are there of drawing an ace from one deck of cards and a diamond from a second deck of cards.?? Need help on this one.





Thanks

Some Counting Principal Questions! Help!!!?
Yeah you have the hang of it.





Let me do the last one.


There are 4 ways of choosing an ace, and 13 ways of choosing a diamond. So combined, that%26#039;s 4*13 = 52
Reply:d) Probability of drawing ace = 4/52


Probability of drawing a diamond = 13/52


Probability of drawing an ace and a diamond = (4/52)(13/52) = 52/2704 = 1/52





Others look OK.
Reply:a) Assuming this means %26quot;one pair of each style in each size and each colour%26quot;, then you have the right number of pairs - but you need to multiply by 2 to get the number of shoes.





b) Correct.





c) Correct logic, but 5×3×2×4 = 120.





d) There are 4 aces and 13 diamonds in any standard deck of cards. So there are 4 ways to draw the ace and 13 ways to draw the diamond, for a total of 4×13 = 52 ways.


(The reason they are specified to be in different packs is that the answer changes if they are in the same pack and you don%26#039;t put the ace back before drawing the diamond.)
Reply:d. 4/52 for the ace 13/52 for the diamond. so to get both the probability is (4/52)*(13/52)=1/52
Reply:a. right


b. right


c. it is 5x3x2x4 but that is equal to 120


d. ace: 1/13 diamond: 1/4



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